{"id":17607,"date":"2024-03-27T05:10:32","date_gmt":"2024-03-27T05:10:32","guid":{"rendered":"https:\/\/soicau4018.minhngocxoso.com\/tinh-xac-suat-lo-de-va-lua-chon-cach-choi-lo-de-hieu-qua\/"},"modified":"2024-03-27T05:10:32","modified_gmt":"2024-03-27T05:10:32","slug":"chia-se-cach-tinh-xac-suat-de-trung-1-con-lo","status":"publish","type":"post","link":"https:\/\/xsmbmienphi.com\/chia-se-cach-tinh-xac-suat-de-trung-1-con-lo\/","title":{"rendered":"chia s\u1ebb c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t \u0111\u1ec3 tr\u00fang 1 con l\u00f4"},"content":{"rendered":"
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T\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec ? \u0110\u00e2y l\u00e0 c\u00e1ch t\u00ednh nhanh \u0111\u1ec3 bi\u1ebft m\u00ecnh c\u00f3 bao nhi\u00eau c\u01a1 h\u1ed9i tr\u00fang l\u00f4 v\u00e0 tr\u00fang \u0111\u1ec1. D\u1ef1a v\u00e0o x\u00e1c su\u1ea5t c\u1ee5 th\u1ec3 ch\u00fang ta s\u1ebd nh\u1eadn th\u1ea5y r\u1eb1ng vi\u1ec7c ch\u01a1i l\u00f4 \u0111\u1ec1 l\u00e0 kh\u00f3 hay d\u1ec5.<\/p>\n

B\u00ean c\u1ea1nh \u0111\u00f3, vi\u1ec7c hi\u1ec3u \u0111\u01b0\u1ee3c t\u1ef7 l\u1ec7 tr\u00fang qua x\u00e1c su\u1ea5t s\u1ebd gi\u00fap anh em t\u00ecm \u0111\u01b0\u1ee3c ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i hi\u1ec7u qu\u1ea3. H\u00e3y c\u00f9ng t\u00ecm hi\u1ec3u chi ti\u1ebft trong b\u00e0i vi\u1ebft n\u00e0y.<\/p>\n

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T\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 v\u00e0 l\u1ef1a ch\u1ecdn c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3<\/p>\n<\/div>\n

T\u00ednh x\u00e1c su\u1ea5t tr\u00fang 1 con l\u00f4<\/h2>\n

Ch\u00fang ta s\u1ebd ch\u1ec9 n\u00f3i v\u1ec1 vi\u1ec7c tr\u00fang L\u00f4 ch\u1ee9 kh\u00f4ng n\u00f3i v\u1ec1 vi\u1ec7c tr\u00fang 2 nh\u00e1y hay 3 nh\u00e1y. Ch\u00fang ta ch\u1ec9 t\u00ednh l\u00e0 Tr\u00fang L\u00f4.<\/p>\n

\u0110\u1ec3 t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 cho vi\u1ec7c tr\u00fang l\u00f4. B\u00e0i to\u00e1n tr\u00fang l\u00f4 = 1 \u2013 (x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00f4) \u2013 1 \u2013 0,99^27 (quay 27 s\u1ed1 \u0111\u1ec1u tr\u01b0\u1ee3t) = 23,7657 %.<\/p>\n

Nh\u01b0 v\u1eady, t\u1ef7 l\u1ec7 tr\u00fang 1 con l\u00f4 trong m\u1ed9t ng\u00e0y ch\u00fang ta ch\u1ec9 c\u00f3 23,7657 ph\u1ea7n tr\u0103m<\/strong>.<\/p>\n

T\u00ednh x\u00e1c su\u1ea5t tr\u00fang 1 con \u0111\u1ec1<\/h2>\n

X\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 th\u00ec qu\u00e1 \u0111\u01a1n gi\u1ea3n. C\u00e1i n\u00e0y ai c\u0169ng t\u00ednh \u0111\u01b0\u1ee3c. N\u1ebfu nh\u01b0 anh em \u0111\u00e1nh 1 con \u0111\u1ec1 th\u00ec x\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 l\u00e0 1\/100 = 1%.<\/p>\n

Nh\u01b0 v\u1eady, ch\u00fang ta ch\u1ec9 c\u00f3 duy nh\u1ea5t 1 ph\u1ea7n tr\u0103m<\/strong> \u0111\u1ec3 tr\u00fang \u0111\u1ec1 n\u1ebfu nh\u01b0 ch\u00fang ta \u0111\u00e1nh 1 con \u0111\u1ec1.<\/p>\n

Ph\u1ea7n n\u00e0y admin khuy\u00ean anh em n\u00ean \u0111\u00e1nh d\u00e0n \u0111\u1ec1. Nh\u01b0 v\u1eady s\u1ebd c\u00f3 t\u1ef7 l\u1ec7 tr\u00fang cao h\u01a1n vi\u1ec7c ch\u1ec9 \u0111\u00e1nh 1 con duy nh\u1ea5t. C\u00f3 r\u1ea5t nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u mi\u1ec5n ph\u00ed<\/strong> cho d\u00e0n \u0111\u1ec1. Anh em h\u00e3y tham kh\u1ea3o \u0111\u1ec3 t\u00ecm cho m\u00ecnh h\u01b0\u1edbng \u0111i m\u1edbi nha.<\/p>\n

T\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 tr\u00fang l\u00f4 xi\u00ean 2<\/h2>\n

\u0110\u00e1nh l\u00f4 xi\u00ean 2 ch\u00fang ta c\u00f3 2 tr\u01b0\u1eddng h\u1ee3p \u0111\u00f3 l\u00e0: Kh\u00f4ng v\u1ec1 con n\u00e0o ho\u1eb7c ch\u1ec9 v\u1ec1 1 con.<\/p>\n

T\u00ednh x\u00e1c su\u1ea5t cho kh\u00f4ng v\u1ec1 con n\u00e0o<\/strong> = 0,98^27 = 57,957 %.<\/p>\n

X\u00e1c xu\u1ea5t ch\u1ec9 v\u1ec1 1 con:<\/strong><\/h5>\n

Tr\u01b0\u1eddng h\u1ee3p n\u00e0y l\u1ea1i chia ra 2 tr\u01b0\u1eddng h\u1ee3p nh\u1ecf l\u00e0 con th\u1ee9 nh\u1ea5t v\u1ec1, con th\u1ee9 2 kh\u00f4ng v\u1ec1 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i. N\u00ean x\u00e1c xu\u1ea5t ch\u1ec9 v\u1ec1 1 con = 2 * x\u00e1c su\u1ea5t tr\u00fang 1 l\u00f4 * x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 = 2 * 23,7657% * 0,99^27 = 36,238%.<\/p>\n

X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2<\/strong><\/h5>\n

X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 2 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con = 57,957% + 36,238% = 94,195%.<\/p>\n

X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2<\/strong><\/h5>\n

100% \u2013 X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang = 100 \u2013 94,195% = 5,8%.<\/p>\n

Nh\u01b0 v\u1eady, ch\u1ec9 t\u00ednh ri\u00eang cho t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 \u0111\u1ec3 tr\u00fang l\u00f4 xi\u00ean 2. Ch\u00fang ta ch\u1ec9 c\u00f3 5,8 ph\u1ea7n tr\u0103m<\/strong>.<\/p>\n

T\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/h2>\n
C\u00e1ch t\u00ednh t\u01b0\u01a1ng t\u1ef1 nh\u01b0 tr\u00fang l\u00f4 xi\u00ean 2.<\/h5>\n

X\u00e1c kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 3<\/strong> = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 3 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 2 con = 0,97^27 + 3 * 23,7675% * 0,98^27 + 3 * 5,8% * 0,99^27 = 98,527%.<\/p>\n

X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/strong> = 100% \u2013 98,527% = 1,473%<\/strong><\/p>\n

Nh\u01b0 v\u1eady, khi anh em \u0111\u00e1nh l\u00f4 xi\u00ean 3 th\u00ec x\u00e1c su\u1ea5t tr\u00fang ch\u1ec9 d\u1ec5 h\u01a1n \u0111\u00e1nh \u0111\u1ec1 m\u1ed9t ch\u00fat.<\/p>\n

T\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 v\u00e0 \u0111\u1ec1 3 ch\u00e2n<\/h2>\n

C\u00f2n \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 \u0110\u1ec1 3 C\u00e0ng v\u00e0 L\u00f4 3 S\u1ed1. H\u00ecnh th\u1ee9c \u0111\u1ec1 3 c\u00e0ng r\u1ea5t kh\u00f3 \u0111\u1ec3 tr\u00fang. C\u00f2n l\u00f4 3 s\u1ed1 th\u00ec c\u00f3 v\u1ebb d\u1ec5 h\u01a1n m\u1ed9t ch\u00fat.<\/p>\n

X\u00e1c xu\u1ea5t tr\u00fang \u0111\u1ec1 3 c\u00e0ng<\/strong> l\u00e0 1\/1000 = 0,1 %.<\/strong><\/p>\n

X\u00e1c xu\u1ea5t tr\u00fang l\u00f4 3 ch\u00e2n<\/strong> = 1 \u2013 x\u00e1c xu\u1ea5t t\u1ea1ch l\u00f4 3 ch\u00e2n = 1 \u2013 0,999^27 = 2,67 %.<\/strong><\/p>\n

N\u1ebfu anh em n\u00e0o \u0111\u00e1nh tr\u00fang \u0111\u1ec1 3 c\u00e0ng th\u00ec qu\u1ea3 th\u1eadt r\u1ea5t may m\u1eafn.<\/p>\n

Nh\u00ecn nh\u1eadn s\u1ed1 l\u00f4 \u0111\u1ec1<\/h2>\n

B\u00ean tr\u00ean l\u00e0 t\u00ednh to\u00e1n c\u1ee5 th\u1ec3 \u0111\u1ec3 anh em th\u1ea5y \u0111\u01b0\u1ee3c r\u1eb1ng ch\u00fang ta c\u00f3 bao nhi\u00eau c\u01a1 h\u1ed9i tr\u00fang l\u00f4 \u0111\u1ec1 h\u00e0ng ng\u00e0y. Anh em h\u00e3y xem l\u1ea1i c\u00e1ch ch\u01a1i c\u1ee7a m\u00ecnh trong th\u1eddi gian qua c\u00f3 th\u1ef1c s\u1ef1 t\u1ed1i \u01b0u cho vi\u1ec7c tr\u00fang l\u00f4 \u0111\u1ec1 hay ch\u01b0a. C\u00e1c ph\u01b0\u01a1ng ph\u00e1p b\u00ed k\u00edp soi c\u1ea7u<\/strong> c\u1ee7a m\u00ecnh cho ra s\u1ed1 \u0111\u00e3 ch\u00ednh x\u00e1c ch\u01b0a.<\/p>\n

N\u1ebfu nh\u01b0 anh em nh\u1eadn th\u1ea5y c\u00e1ch m\u00ecnh \u0111ang ch\u01a1i qu\u00e1 m\u1ea1o hi\u1ec3m v\u00e0 t\u1ef7 l\u1ec7 th\u1eafng l\u00e0 kh\u00f4ng cao. Anh em h\u00e3y k\u1ebft h\u1ee3p c\u00e1c c\u00e1ch ch\u01a1i kh\u00e1c nhau \u0111\u1ec3 t\u1ef1 m\u00ecnh t\u1ea1o ra c\u01a1 h\u1ed9i chi\u1ebfn th\u1eafng cho ch\u00ednh m\u00ecnh.<\/p>\n

B\u1ea3n th\u00e2n Admin h\u00e0ng ng\u00e0y v\u1eabn \u0111\u00e1nh c\u1ea3 l\u00f4 l\u1eabn \u0111\u1ec1. V\u1edbi \u0111\u00e1nh l\u00f4, ngo\u00e0i v\u00e0i s\u1ed1 l\u00f4 \u0111\u00e1nh ng\u00e0y th\u00ec m\u00ecnh c\u00f2n ch\u01a1i l\u00f4 khung \u0111\u1ec3 \u0111\u1ea3m b\u1ea3o s\u1ef1 chi\u1ebfn th\u1eafng. C\u00f2n v\u1edbi \u0110\u1ec1 th\u00ec m\u00ecnh kh\u00f4ng \u0111\u00e1nh b\u1ea1ch th\u1ee7 \u0111\u1ec1. M\u00ecnh lu\u00f4n ch\u01a1i d\u00e0n \u0111\u1ec1 nh\u1eb1m n\u00e2ng cao t\u1ef7 l\u1ec7 th\u1eafng cu\u1ed9c.<\/p>\n

V\u00ed d\u1ee5 n\u1ebfu ch\u1ec9 \u0111\u00e1nh 1 con \u0111\u1ec1 th\u00ec t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 r\u00f5 r\u00e0ng ch\u1ec9 c\u00f3 1% tr\u00fang. C\u00f2n Admin \u0111\u00e1nh d\u00e0n \u0111\u1ec1 40 s\u1ed1 th\u00ec c\u00f3 \u0111\u1ebfn 40% kh\u1ea3 n\u0103ng th\u1eafng cu\u1ed9c.<\/p>\n

C\u0169ng nh\u01b0 v\u1eady, anh em n\u00ean t\u00ecm ra c\u00e1ch ch\u01a1i cho ri\u00eang m\u00ecnh th\u1eadt hi\u1ec7u qu\u1ea3. C\u00f3 nh\u01b0 v\u1eady vi\u1ec7c \u0111\u00e1nh l\u00f4 \u0111\u1ec1 c\u00f3 chi\u1ebfn th\u1eafng s\u1ebd d\u1ec5 d\u00e0ng h\u01a1n r\u1ea5t nhi\u1ec1u.<\/p>\n

T\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 l\u00e0 ki\u1ebfn th\u1ee9c kh\u00f4ng th\u1ec3 b\u1ecf qua cho t\u1ea5t c\u1ea3 anh em ch\u01a1i l\u00f4 \u0111\u1ec1. Anh em h\u00e3y t\u00ecm hi\u1ec3u v\u00e0 ghi nh\u1edb ch\u00ednh x\u00e1c nh\u1eefng th\u00f4ng tin trong b\u00e0i vi\u1ebft n\u00e0y. \u0110\u1ec3 vi\u1ec7c \u0111\u00e1nh l\u00f4 \u0111\u1ec1 tr\u1edf l\u00ean d\u1ec5 d\u00e0ng tr\u00fang th\u01b0\u1edfng h\u01a1n. Ch\u00fac anh em lu\u00f4n may m\u1eafn v\u00e0 chi\u1ebfn th\u1eafng.<\/p>\n<\/div>\n<\/div>\n<\/div>\n